Hooknswoop

Vector 2 Derek

Not always. Especially with a larger main. Remember, containers have the same size reserve PC for the largest and smallest reserves. Reserve PC's are not made bigger for bigger reserves. With a large main and reserve, there may not be enough speed from the main and enough drag from the PC to deploy the reserve. Derek

If the question had been, "Can windshear or turbulence cause a canopy to dive more?", then the answer would be yes, it can, and it can also cause it to dive less. But that wasn't the question. We do fly by ground refernce, but a canopy doesn't dive any more because there is wind and I don't change my inputs into the canopy if there is wind. Derek

Figured I would answer my own question

It depends on how deep in the brakes you are. If you are very deep in the brakes, you could stall one side of the canopy by pulling down the toggle anymore. Then it is necessary to let one toggle up a bit to get the turn. You can also pull one toggle down a little and let the other up a little to get the turn. Practicing all 3 techniques before yo need them is important. Derek

Standard air pressure is 29.92 or 14.7 psi. 18,000 feet MSL, is about 1/2 an atmosphere or 7.35 PSI. So, figure 13,500 back to sea level, depending on the DZ. Derek

A high speed or acclerated stall can be done with either toggles or rear risers. With rear risers, it will stall at a much higher airspeed than with toggles. With toggles, as you pull down, you are increasing the angle of attack the canopy will stall at. By pulling hard and quick enough, the canopy will stall at a higher airspeed than it normally would. With toggles, you are changing the shape of the airfoil. The more you pull down trying to stall the canopy, the more you are increasing the angle of attack the canopy will stall at. You have to pull them down fast enough, creating enough "G" forces (which raises the airspeed the canopy will stall at) to out pace the stall speed reducing effect the toggles have. Derek

The angle of attack a canopy will stall at is much lower on rear risers than on the toggles, hence the higher stall speed. A canopy will stall at a much lower airspeed using the toggles because the shape of the airfoil is being changed to one that can fly at lower airspeeds. This is similar to lower the flaps on an airplane to lower the stall speed. So an airfoil stalls at the same angle of attack, regardless of airspeed, unless you change the shape of the airfoil. Derek

I meant if you ‘magically’ take away the wind. Just trying to illustrate a point Right, but wind shear and turbulence is different than just wind. All bets are off when it comes to wind shear and turbulence. Derek

What was your longest free-fall? What type of jumpsuit and what type of dive? Exit and opening altitude? Derek

Glad you are OK. Also glad you aren't double stowing. Hell man, you are jumping a Xfire. Take care, Derek

Some posting guidelines for Gear and Rigging. 1. Keep topics to gear and rigging. 2. One-liners, post whoring, and personal messages should either be in Talkback or via PM. 3. Don’t post angry. 4. Understand that an issue can have no “right” answer. 5. Before posting, do a search on the topic to prevent repetition of the same thread. 6. There are no dumb questions. 7. Whenever possible back up statements with references, data, etc. 8. Respect other’s opinions. 9. No one is always right. Thanks, Derek

If the main doesn't have enough speed, the reserve PC won't extract the free bag from the container. What you really don't want is for the bag to pass up the PC (PC in burble, bag takes off) and then the PC go through the reserve lines. I know of at least on reserve malfunction that was caused by the bag leaving while the PC was in the burble. Derek

I think he is looking for reserve manuals and PD just updated their reserve manual. Derek

It's not about right or wrong. It is about learning.

Yes

Fair enough

For the 0 mph current, 200 foot wide river, swimming at a 45-degree angle: 2 mph=2.93 FPS A right triangle w/ 200 foot sides has a Hypotenuse of 282.84 feet. (a^2+b^2=c^2) At 2.93 FPS it takes 96.53 seconds to travel 282.84 feet. For the 20 mph current and swimming upstream at a 45-degree angle: Swimming upstream at 2.93 fps breaks down to a 2.07 fps vector directly across the stream. {Sine 45= opposite/2.93}= 2.07 This means the resulting vector is 27.937 fps with an angle downstream of 4.25 degrees. {29.33-2.07=27.86}{(27.86^2 + 2.07^2 = RV^2)= 27.937}{Inverse sine x = 2.07/27.937} = 4.25 degrees. So the swimmer’s actual direction over the ground is 4.25 degrees from the shoreline. His resultant speed over the ground is 27.937 fps. The distance he will actually travel is 2638.75 feet. {(sin 4.25 = 200 / TD) = 2698.75} The distance downstream he will travel is 2691.33 feet. {(DS^2 + 200^2 = 2698.75^2) = 2691.33) It will take the swimmer 96.60 seconds to travel 2838.77 feet at 29.40 fps. {(2838.77 feet/29.40 fps) = 96.56 seconds} The difference of 96.53 seconds and 96.60 (0.07 seconds) seconds is because I only took it out 2 places and rounding. Derek

From my canopy course: The initial part of the flare stops your descent, as you continue to flare, it stops your forward movement. When landing in windier conditions, the parachute’s ground speed will reach zero when the airspeed becomes equivalent to the wind speed. In other words, when landing facing a 10-mph headwind, the parachute’s airspeed needs to be slowed to 10 mph in order to create a zero ground-speed landing. You will note that your canopy can sustain flight at 10 mph for a longer period of time than it can dwell at the stall point. This will create a longer floating phenomenon at the end of the surf when landing on days with some wind and explains why you have to “flare less” on windy days. Derek

http://virtualskies.arc.nasa.gov/weather/youDecide/climbPreformChart.html This is a link to a climb performance chart. It does not take uinto account the winds, because they have no effect. I'm working on a diagram for my math. Derek

Good idea

Because a head wind reduces the ground roll before reaching the airspeed required to fly. Takes less runway to take off and reduces wear on the tires. The airpseed at which an aircraft takes off at is not affected by the amount of wind. It still needs the same airspeed, but it reaches that sirpeed sooner since it starts it's ground roll with airspeed i.e. wind. Derek

Exactly, it makes no difference, to a submarine or to a canopy. Derek

I have been listening and you have not explained the physics or aerodynamics of your position. Exactly, and the current has no effect on how mcuh a submarine weighs. I'll answer it for you. The same. It will submerge the same regardlessof the current. A canopy does not dive any longer or faster if there is wind or not. Why would it? Derek

Exactly. A canopy's shape doesn't change because of the wind. It has the same descent rate, regardless of the wind. I'm not a submarine pilot, but I have 500+ hours underwater. It doesn't. Not likely that it will answer, but if it does, why? Updrafts, yes. Wind, no. Wind does not create lift. A glider with a 60 mph foward speed flying into a 60 mph headwind cannot hover. It will descend at the same rate as if there was zero wind. A glider needs updrafet/thermals to climb or sustain altitude without trading airspeed. Yes, the water is the largest force, but depending on strength of the wind, it cannot be discounted. No, you won't. Your groundspeed would be higher, but you wouldn't reach the other side any quicker than with zero current. Do the math. No, it won't. Ask any pilot, including me. Wind does not affect the descent rate of an aircraft. More speed, more ground speed (or less or no efecct at all depending on the direction of the sircraft and wind), no more airspeed or descent rate. Derek