Need Math help.

[warpedskydiver 0]

He drives a GTO

Let's just face it, sometimes calculation is what is needed, and sometimes real measurements are absolutley neccessary.

[Remster 30]

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That's why I said unfortunatley, velocity for him would not be a constant, and actually is would be a somewhat spiral curve(but not exactly), instead of a straight line.

We could all calculate this to death and be very wrong, or measure it with the means I suggested,and get the actual answer.

No offence, but I dont think you understand motion equations.

The equation I posted does not asume constant V. It assume constant Acceleration.

you have x = 32 yards; Vinitial = 0; a= watever you calculated based on your acceleration on 0 - 60 number (basically, 60mph * 3600 / 60 seconds in mps). Convert that in yards/s2

So you can find t to reach 32 yards, and then, again, assuming constant acceleration, figure out what speed you were at at time = t

Remster

[warpedskydiver 0]

I agree with your statement, however I know the velocity would not be a constant at all, and might be highly improbable to calculate.

I have an old friend, Mark Krupa who used to be a TF racer, until he installed the device accelerometer and an ET computer he never established the correct data.

[Icon134 0]

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I agree with your statement, however I know the velocity would not be a constant at all, and might be highly improbable to calculate.

Of course the Velocity wouldn't be constant... He is accelerating...

Livin' on the Edge... sleeping with my rigger's wife...

[Darius11 12]

Thank you all who tried I am out of here in 30 min. wish me luck.

I'd rather be hated for who I am, than loved for who I am not." - Kurt Cobain

[rehmwa 2]

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I know the velocity would not be a constant at all

what's wrong with you people?

the basic assumption in his question is constant positive acceleration - equations for distance and velocity (as functions of time) based on constant acceleration is VERY simple

pissing all over the problem statement is normal for certain types of people: those that know they can't solve the simple equation and can't admit it; bored web surfers; engineers trying to ensure job security

x(t=0) = 0
v(t=0) = 0

v = f(t) = At where A is constant

integrate to get x

solve for t for any v or x and plug it back in to get the other

I saw it once in here - and a bunch of incorrect linear equations in other posts.

If he's looking for the "actual" answers for a specific model vehicle, then I'd suggest going to the manufacturer's literature and looking it up.

Edit; Pay the fine - you got caught and man up to it.

...
Driving is a one dimensional activity - a monkey can do it - being proud of your driving abilities is like being proud of being able to put on pants

[Darius11 12]

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you got caught and man up to it.

Yep always have. this is not one of the times when i was caught.

This is a cop who treated me like you see in these movies. He was yelling and treating me and egging me on to take a swing at him or to curse at him.

I remained calm as I was not even in my car when he gave me the ticket. I was at a gas station parked and out of my car in the store paying for my shit.

The dude must have thought I was someone else that’s the only explanation.
The story is long, but I have to go to court now.

Peace

I'd rather be hated for who I am, than loved for who I am not." - Kurt Cobain

[rehmwa 2]

well then, good luck, ask for the onboard video (except you weren't near his car, I suppose)

no reason for a cop to be emotional about his job - it's a job. as soon as they start taking it personal, it's time for them to drive a desk for a while.

I think time outs are good things for a lot of professions.

...
Driving is a one dimensional activity - a monkey can do it - being proud of your driving abilities is like being proud of being able to put on pants

[SivaGanesha 2]

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Can anyone help me?
Please write formula so I know how to do it.

If you know the maximum velocity the car could possibly attain, there is a formula on the following page that I suspect would provide a pretty close approximation:

Stokes friction

Knowing the car's maximum velocity (perhaps 110mph), its velocity after 5.8 sec (60mph), and its initial velocity (0mph) would allow you to solve for the unknowns in the above equation, and then determine the speed after 32 yards. As quade says this involves certain assumptions but I think the approximation would be pretty close. You do need one more piece of information beyond what you provided--the car's maximum velocity.

"It's hard to have fun at 4-way unless your whole team gets down to the ground safely to do it again!"--Northern California Skydiving League re USPA Safety Day, March 8, 2014

[kbordson 8]

First get the average velocity (assuming constant acceleration)

v avg = 1/2 (v0+v)

30 = 1/2 (0 + 60)

30mph average velocity (which is 0.0083 miles/sec or 14.6 yards/sec)




Then displaced area would be:

change in x = v avg *t

0.048miles = 0.0083m/sec * 5.8sec
or
84.68yards = 0.048 yards/sec * 5.8sec


In 32yrds (this one makes me wish I remember my calculus better)

assuming a constant acceleration:

That would be only 2.6sec of acceleration. (84/32yds = 2.625)

velocity = acceleration * time

acceleration = 60mph/5.8sec => 0.00287miles/sec2 (5.0yards/sec2)

velocity = 0.00287miles/sec2 * 2.6sec => 0.00746miles/sec => 26.8mph



(disclaimer - do not get medical information or math help from the internet )

[livendive 8]

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Thanks man
I kind of thought it would be impossible, but I figured I would try to see if one of the brilliant minds we have on here could figure it out. I have been out of school so long I can’t remember 99% of the formulas I learned.

Assuming you didn't wreck the car while getting the ticket, do the following. Put some premium fuel in it, take it to a private parking lot, put some flags up 32 yards apart, and videotape yourself flooring it from a dead stop at one till you pass the other. If it isn't a particularly fast car, I doubt you'll see over 20 mph, and if that got you a ticket, it must have been in a school zone, in which case you deserve it.

Blues,
Dave

"I AM A PROFESSIONAL EXTREME ATHLETE!"
(drink Mountain Dew)

[JackC 0]

We have v=60mph and t=5.8s
So assuming constant acceleration

a=(v-v0)/t = 60 * 0.44703 / 5.8 = 4.6244 m/s^2

where 1 mph = 0.44703 m/s

We now have distance (32yds) and acceleration (4.62m/s^2) and we want speed.

Rearange the constant acceleration formula:

x-x0=(v^2-v0^2)/(2*a)

to give

v = sqrt(2*a*x)

where x0=0 and v0=0 assuming a standing start.

1 yd = 0.9144 m

So

v = sqrt (2 * 4.6244 * 32 * 0.9144) = 16.451 m/s =36.8 mph

I think that's right but I've had a beer or three.

[Darktreader 0]

certain variables have not been included in the equation.

1. was there tire spin!! you can accelerate a 0-60 in 10 sec -car to100 mph without moving one inch under tire spin

2. the size of the tire will determine distance traveled no matter what speed you are at. its how many revolutions the tire made mutiplied by the circumference that gives you the distance traveled

what is needed for this equation to be accurate is your peticular tire circumferance and how many revalutions your cars tires make while accelerating to maximum speed of 60 mph without spinning your tires from a stop position.

This is an accurate way to measure the distance your car woudl travel when 60 mph is reached, if its drastically further then 32 yards then you have an arguement.


Either way it probably wount get you out of a ticket.

"Before we waste time talking and getting to know each other, let's just have sex once and see if we're compatible"

[Darktreader 0]

futhermore your car will travel 29.33 yards per sec at 60 mph.

this number changes at lower speeds.

To calculate what speed your at, at 32 yards from a stoped position,.

we need to know how far it takes your car to reach 60 mph.

then a solution can be made

"Before we waste time talking and getting to know each other, let's just have sex once and see if we're compatible"

[jcd11235 0]

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We have v=60mph and t=5.8s
So assuming constant acceleration

a=(v-v0)/t = 60 * 0.44703 / 5.8 = 4.6244 m/s^2

where 1 mph = 0.44703 m/s

We now have distance (32yds) and acceleration (4.62m/s^2) and we want speed.

Rearange the constant acceleration formula:

x-x0=(v^2-v0^2)/(2*a)

to give

v = sqrt(2*a*x)

where x0=0 and v0=0 assuming a standing start.

1 yd = 0.9144 m

So

v = sqrt (2 * 4.6244 * 32 * 0.9144) = 16.451 m/s =36.8 mph

I think that's right but I've had a beer or three.

I arrived at the same answer.

Math tutoring available. Only $6! per hour! First lesson: Factorials!

[Lindsey 0]

I thought you Arabs created math. Why are you asking THESE people? Heh....

Peace~
linz

--
A conservative is just a liberal who's been mugged. A liberal is just a conservative who's been to jail

[warpedskydiver 0]

Sounds about right, and a far cry from the 11.285mph that Quade calculated.

My friend Mark said add 150mph to that 36mph, in the same distance (96ft) then your talking!

[quade 4]

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Sounds about right, and a far cry from the 11.285mph that Quade calculated.

My friend Mark said add 150mph to that in the same distance (96ft) then your talking!

Heheh.

quade -
The World's Most Boring Skydiver

[warpedskydiver 0]

The guy has damage to his neck from launching so hard

He once held the worlds record for a 60ft time.

For almost a year.

[warpedskydiver 0]

The year he retired he rolled his rail seven times before hitting the pavement.

His rear right tire blew as it got really tall.

The video showed a bottle cap on the track.

[warpedskydiver 0]

Here is what he is doing in his retirement, a much slower pace too!
9/30/07- "Mad" Mark Krupa @ Union Grove, WI
Chicago Wise Guys
Mark takes the win driving the Dean Cameron owned and tuned DRC Firebird

Mark says low 7s are much more relaxing of a sunday drive than the low 5s were.

He just hung up, and washed up for dinner.

[DrewEckhardt 0]

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I would even love to know the answer based on constant acceleration if someone has that.

60 miles per hour = 88 feet per second.

Yeah, but acceleration is not a constant 88 feet/second^2 because the car's torque curve isn't flat even when you don't shift and aerodynamics conspire against you at higher speeds.

You might take 2 seconds to reach 30 MPH and 3.8 to finish getting to 60 MPH.

[pBASEtobe 0]

Are you people serious?!?

[jasonRose 0]

Read this...

http://www.worldlawdirect.com/article/903/Fighting_a_speeding_ticket.html

Some day I will have the best staff in the world!!!

[quade 4]

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I would even love to know the answer based on constant acceleration if someone has that.

60 miles per hour = 88 feet per second.

Yeah, but acceleration is not a constant 88 feet/second^2 because the car's torque curve isn't flat even when you don't shift and aerodynamics conspire against you at higher speeds.

You might take 2 seconds to reach 30 MPH and 3.8 to finish getting to 60 MPH.

I believe I made that abundantly clear earlier on.

Further . . . yeah, the logic was tortured. That wasn't just admitted to earlier but explicitly pointed out.

quade -
The World's Most Boring Skydiver