Solve this.

[SarahC07 0]

A + B + C = M

M *0.025 = A

A = unknown
B and C have definite values

When rounding to two decimal places, it's almost impossible to make M *0.025 = A everytime.

Can anyone develop a formula for this?

[jtval 0]

8

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[SarahC07 0]

Cute but I didn't give you any values. Next.

[jtval 0]

I didn't need to add values. Just plug in 8 and it is forcing it to work.

Quote

8 +8 +8 = 8

8 *8= 8

8 = unknown
8 and 8 have definite values

When rounding to two decimal places, it's almost impossible to make 8 *8 = 8 everytime.

Can anyone develop a formula for this?

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[shropshire 0]

42

(.)Y(.)
Chivalry is not dead; it only sleeps for want of work to do. - Jerome K Jerome

[jtval 0]

Quote

42

Wow, Until you plugged that nuimber in I didn't think it would work.

Very sharp eye.
See Sarah, We're all here to help.

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[Broke 0]

0 plug it in and you find it works :P

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[ghost47 18]

Quote

A + B + C = M

M *0.025 = A

A = unknown
B and C have definite values

When rounding to two decimal places, it's almost impossible to make M *0.025 = A everytime.

Can anyone develop a formula for this?

When you say develop a formula for "this", what is "this"?

Since you haven't limited A, B, C, or M to integers

A = (B+C) / (-0.975)
B = -C -0.975A
C = -B -0.975A
M = A/0.025 or ((B+C)/(-0.975)(0.025)) or (B+C)/(-0.024375)

Beyond that, I don't think there's much you can do without specific values.

(Edited to fix an error)

[airdvr 210]

I'm gettin' a headache

Please don't dent the planet.

Destinations by Roxanne

[nanook 1]

M=A/.025+B+C

But my degree is in Business

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